Transfer gold between Horde/Alliance without the 15% cut menu

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  1. #16
    c0rrupt10n's Avatar Member
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    Thanks, it worked like a charm!

    Transfer gold between Horde/Alliance without the 15% cut
  2. #17
    aamlord's Avatar Active Member
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    Seriously? Looking at the math, one would think you need to set a very high amount to take advantage of 32-bits rollover. But if it does work, then it seems Blizz needs to work on their cut calculation instead of multiplying by 15 then divide by 100.

    OTOH if it's divide by 100 then multiply by 15, you will need a lot more than 28kg to avoid neutral AH fees.

    Perhaps a SS of seller's money (with name blacked out naturally), showing the total amount from AH item and the cut would help prove or disprove this.

  3. #18
    Killerpet's Avatar Member
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    Originally Posted by aamlord View Post
    OTOH if it's divide by 100 then multiply by 15, you will need a lot more than 28kg to avoid neutral AH fees.
    If its divide by 100 1st then its impossible to avoid fees

  4. #19
    gryphons53's Avatar Member
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    Originally Posted by UnoriginalGuy22 View Post
    WoW has an absolute gold limit of 214748 gold, 36 silver and 47 copper. So this will not work and it will not overflow. Nice try though.

    Also:
    286331154 * 15 = 4294967310

    Is wrong, it is 15% e.g.
    286331154 * .15 = 42949673.1

    Or rounded (as WoW does) to 42949673. As 42,949,673 is far smaller than 2,147,483,647 it won't overflow or break WoW.
    not gonna bother checking your math since u cant read... hes talking 29k gold, youre talking 215k

  5. #20
    Killerpet's Avatar Member
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    Originally Posted by UnoriginalGuy22 View Post
    WoW has an absolute gold limit of 214748 gold, 36 silver and 47 copper. So this will not work and it will not overflow. Nice try though.

    Also:
    286331154 * 15 = 4294967310

    Is wrong, it is 15% e.g.
    286331154 * .15 = 42949673.1

    Or rounded (as WoW does) to 42949673. As 42,949,673 is far smaller than 2,147,483,647 it won't overflow or break WoW.
    Originally Posted by gryphons53 View Post
    not gonna bother checking your math since u cant read... hes talking 29k gold, youre talking 215k
    what UnoriginalGuy22 says is true to a certain extent since the limit for gold would be 2,147,483,647 which is the decimal of 7FFF FFFF (max for a signed number). The number however must go above 2 x 2,147,483,647 to go above FFFF FFFF and be reset to 0000 0000. now since 2 x 2,147,483,647 = 4,294,967,295 and this is less than 4,294,967,310 this causes an overflow

    +4,294,967,310
    - 4,294,967,295
    -----------------------
    +0,000,000,015

    TL;DR The number when multiplied by 15 (or 10) must be above 4,294,967,295 (or 429496g 72s 95c)
    Last edited by Killerpet; 03-08-2009 at 11:21 PM.

  6. #21
    darko999's Avatar Member
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    Work! on private server, tested i don't know if this work on retail, and if it is risk or not

  7. #22
    surfsem's Avatar Member
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    Originally Posted by c0rrupt10n View Post
    Thanks, it worked like a charm!
    Ya sure...?
    Hey whats sup Im a wow addict wanna go out some time?

  8. #23
    sid1488's Avatar Active Member
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    i didn't understand shite tbh lol
    I am Swedish and I like green! And most other colours too!

  9. #24
    Grizzam's Avatar Member
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    I tested this on the PTR, it did not work, and the PTR is about as close to retail as you're going to get when compared to private servers.

  10. #25
    Simonneke's Avatar Member
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    Anyone with a screenshot? 2 Yes 1 No test atm

  11. #26
    keksbirne's Avatar Active Member
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    Wow gold value is signed int32, this got profen already.
    And I strongly doubt that blizzard has programmers that calculate fees with the risk of getting an overflow by first multiplying...

  12. #27
    Killerpet's Avatar Member
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    Originally Posted by sid1488 View Post
    i didn't understand shite tbh lol
    Ill try explain. When people are counting they count like this:

    0,1,2,3,4,5,6,7,8,9 and then start all over again with a 1 in front of it 10,11,12,13,14,15,16,17,18,19 and they keep on going. changing the highest number every time they get past 9. this is called base 10 because there are 10 different numbers

    To make things easier to understand when looking at data people look at it in terms of hex or base 16. this means it counts from 0 to 15 then changes the highest number afterwards.

    We then use letters for the numbers after nine

    This comes out as:
    Code:
    DECIMAL:     0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
    HEXADECIMAL: 0 1 2 3 4 5 6 7 8 9  A  B  C  D  E  F
    So counting from 0 - 39 looks like this:
    Code:
    Dec	Hex	|	Dec	Hex
    00	00	|	20	14
    01	01	|	21	15
    02	02	|	22	16
    03	03	|	23	17
    04	04	|	24	18
    05	05	|	25	19
    06	06	|	26	1A
    07	07	|	27	1B
    08	08	|	28	1C
    09	09	|	29	1D
    10	0A	|	30	1E
    11	0B	|	31	1F
    12	0C	|	32	20
    13	0D	|	33	21
    14	0E	|	34	22
    15	0F	|	35	23
    16	10	|	36	24
    17	11	|	37	25
    18	12	|	38	26
    19	13	|	39	27


    So you see, each time we get to an F and try add 1 we make the F = 0 and add 1 to the highest number (just like if we made the 9 = 0 and increase the highest number in base 10)

    If we add 1 to F it becomes 10, if we add 1 to FF it becomes 100, if we add 1 to FFF it becomes 1000 and so on.

    Now if we can only hold enough information in memory for FFFF FFFF (8 F's) and we try add 1 to it we will end up with 1 0000 0000. But like i said, the memory can only see the last 8 digits. So this 1 000 000 becomes 0000 0000.


    Hope this helps you understand, if it doesnt then reply here and i can try a different approach

    -------------------
    If you understood everything above and want to know what signed int32 is it is this:

    There are 32 bits that can either be 0's or 1's
    This looks like this: 00000000000000000000000000000000

    These are split into groups of 4 to make it easier to read
    This looks like this: 0000 0000 0000 0000 0000 0000 0000 0000

    Each of these groups of 4 have 16 different ways they can be arranged:
    0000 -> 0001 -> 0010 -> 0011 -> 0100 -> 0101 -> 0110 -> 0111 -> 1000 -> etc...
    (0 -> 1 -> 2 -> 3 -> 4 -> 5 -> 6 -> 7 -> 8 -> etc...)

    These different arrangements take up the different hex values shown above (0 - F)

    This means that the value of a group of 4 bits can vary from 0000 to 1111 (or 0 to F)

    So instead of each 0000 i will write the hex value:
    We end up with 0 0 0 0 0 0 0 0 up to F F F F F F F F

    Grouping these together into groups of 4 leaves:
    0000 0000 to FFFF FFFF

    Now the first bit of the first number (shown here in bold) tells us if the number is positive or negative (we will assume 0=positive, 1=negative)
    0000 0000 0000 0000 0000 0000 0000 0000

    This means that for a positive number the numbers can go from:
    0000 0000 0000 0000 to 0111 1111 1111 1111
    or
    0000 0000 to 7FFF FFFF

    (Since 0111 = 7 and 1111 = F)



  13. #28
    JaCkaL's Avatar Member
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    well, just post sum enchanting thingy and you wont have to pay a fie... i think

  14. #29
    Killerpet's Avatar Member
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    Originally Posted by JaCkaL View Post
    well, just post sum enchanting thingy and you wont have to pay a fie... i think
    They are talking about the auction houses cut from the seller when an auction is successful. For same faction AH it is 10% (or maybe 5%) and for neutral AH it is 15%

    So even it you put up enchanting mats on neutral AH for 100g it will cost you nothing for the deposit but if it sells you will only get 85g back

  15. #30
    benjamin66's Avatar Banned
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    Originally Posted by Grizzam View Post
    I tested this on the PTR, it did not work, and the PTR is about as close to retail as you're going to get when compared to private servers.

    Do you set the price at 28634g in a Neutral AH?
    if yes then blizzard is fixing this


    Originally Posted by Simonneke View Post
    Anyone with a screenshot? 2 Yes 1 No test atm
    my friend just do this yesterday on a live chinese server
    screenshot:

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