How to start the MySQL? menu

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  1. #1
    TarridoN's Avatar Sergeant
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    How to start the MySQL?

    Alrighty, I compiled my own server (with help thx ) and i have verything ready to go. I installed the MySQL and filled out the information i needed from it. Where do i go or what do i need to start it? Ty
    Last edited by stoneharry; 11-21-2010 at 12:18 PM.

    How to start the MySQL?
  2. #2
    schlumpf's Avatar Retired Noggit Developer

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    Get the sakila demo database.

    Understand these queries:
    --Abfrage 3: Alle Adressen mit voller Anschrift ausgeben
    SELECT a.address_id, concat(a.address,", ",a.address2,", ",a.postal_code," ",c.city,", ",a.district,", ",co.country) AS "Full address"
    FROM address AS a LEFT JOIN city AS c ON a.city_id = c.city_id LEFT JOIN country AS co ON c.country_id = co.country_id;

    -- Abfrage 8: Welcher Kunde hat am meisten Umsatz generiert?
    select concat(c.first_name," ",c.last_name) as "Kunde",sum(amount) AS "Umsatz" from payment AS r LEFT JOIN customer AS c ON c.customer_id = r.customer_id group by r.customer_id order by sum(amount) desc LIMIT 1;

    -- Abfrage 9: Welche Einnahmen haben die Mitarbeiter gemacht?
    select concat(s.name,", ",s.city) as "Mitarbeiter",sum(amount) AS "Einnahmen" from payment AS p LEFT JOIN staff_list AS s ON s.ID = p.staff_id group by p.staff_id order by sum(amount) desc;

    -- Abfrage 10: zeigt an welcher Schauspieler in welchem Film mitspielt.
    Select CONCAT(actor.first_name,' ', actor.last_name) as actorname, film.title
    FROM sakila.actor, sakila.film, sakila.film_actor
    WHERE (actor.actor_id = film_actor.actor_id)
    AND (film.film_id = film_actor.film_id);

    -- Abfrage 11: Gibt alle Filmtitel mit Kategorie und Rating aus
    SELECT f.title AS "Titel", c.name AS "Kategorie", f.rating AS "Rating" FROM film_category AS fc LEFT JOIN category AS c ON fc.category_id = c.category_id LEFT JOIN film AS f ON fc.film_id = f.film_id;

    -- Abfrage 15: Aus welcher Stadt kommen die meisten Kunden
    Select city.city, count(customer_id) from city right join address on address.city_id = city.city_id right join customer on customer.address_id=address.address_id group by city.city_id order by count(customer_id) desc limit 1;

  3. #3
    TarridoN's Avatar Sergeant
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    ?...... I have no clue.. If anyone can help i have teamviewer.

  4. #4
    stoneharry's Avatar Moderator Harry


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    What schlumpf is saying is that you should try to understand what you are doing rather than getting somebody to do it for you and/or copying something. You don't understand what the hell your trying to do, you just know you have to do something. It's really common sense once you understand how databases work...

    Add a prefix when creating threads.

  5. #5
    TarridoN's Avatar Sergeant
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    Mhm.... wow thanks for the help "pal"

  6. #6
    stoneharry's Avatar Moderator Harry


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    I'm not trying to be insulting, it's true.

    You can't expect to just pick up something and be able to use it easily, you need to understand what is happening without all the guides by people who are by no means experts.

  7. #7
    TarridoN's Avatar Sergeant
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    Well... i'm still new to this.

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