Lua Script Help

[B14d3r11]

I am attempting to make a script check to see if the player has a Profession then remove it from the gossip list if they have it and if they already have 2 professions remove them all... Any idea how id do this cause i've tried and tried for about 4 hrs and nuthin...

Heres my Gossip I want setup this way

if(intid == 1) then
    pUnit:GossipCreateMenu(3543, player, 0)
        pUnit:GossipMenuAddItem(0, "Alchemy", 3, 0)
        pUnit:GossipMenuAddItem(0, "Blacksmithing", 4, 0)
        pUnit:GossipMenuAddItem(0, "Enchanting", 5, 0)
        pUnit:GossipMenuAddItem(0, "Engineering", 6, 0)
        pUnit:GossipMenuAddItem(0, "Herbalism", 7, 0)
        pUnit:GossipMenuAddItem(0, "Inscription", 8, 0)
        pUnit:GossipMenuAddItem(0, "Jewelcrafting", 9, 0)
        pUnit:GossipMenuAddItem(0, "Leatherworking", 10, 0)
        pUnit:GossipMenuAddItem(0, "Mining", 11, 0)
        pUnit:GossipMenuAddItem(0, "Skinning", 12, 0)
        pUnit:GossipMenuAddItem(0, "Tailoring", 16, 0)
   pUnit:GossipSendMenu(player)
end

[B14d3r11]

Assistance would be helpful, I will Repx3

[B14d3r11]

Lazyness now adays

[edded]

You could make items that have a shared unigness of 2 and then put this code it

if(intid == 3) then
player:RemoveItem(XXXXX, 1)
player:RemoveItem(XXXXX, 1)
player:RemoveItem(XXXXX, 1)
player:RemoveItem(XXXXX, 1)
player:RemoveItem(XXXXX, 1)
player:RemoveItem(XXXXX, 1)
player:RemoveItem(XXXXX, 1)
player:RemoveItem(XXXXX, 1)
player:RemoveItem(XXXXX, 1)
player:RemoveItem(XXXXX, 1)
player:RemoveItem(XXXXX, 1)
player:AddItem(XXXXX, 1)
player:GossipComplete()
else
player:GossipComplete()
end
end