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  1. #1
    Cypher's Avatar Kynox's Sister's Pimp
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    lolmath

    Math teacher posed the class this question to see who could work it out the fastest because we had nothing better to do, thought I'd repost here and see if anyone could work it out. (It only looks hard, it's not hard if you think about it logically)

    " Simplify and factorise:
    conjugate( ( (lim(n ->inf) sum(k=1)^inf 9/(10^k)) + (sum(m=1)^inf 1/(2^m)))^2 - x^2) / ( lim(p -> inf) 1 - 1/(10^p))! "

    (Syntax of the question has been changed slightly so you can't just dump it into maple. )

    /me is very bored

    First one with the correct answer wins.

    lolmath
  2. #2
    schlumpf's Avatar Retired Noggit Developer

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    Re: lolmath

    conjugate(4-x^2)

  3. #3
    Fault's Avatar Retired Super Moderator

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    Re: lolmath

    i started calc 2 yesterday, GAY!

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  4. #4
    Marlo's Avatar Banned
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    Re: lolmath

    4 + 4

    sorry what was the question again?

  5. #5
    Cypher's Avatar Kynox's Sister's Pimp
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    Re: lolmath

    Originally Posted by schlumpf View Post
    conjugate(4-x^2)

    Closest so far.

    Now find the conjugate of that (easy). Then factorise (easy or hard, depending on the level of math you know).

  6. #6
    Cypher's Avatar Kynox's Sister's Pimp
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    Re: lolmath

    Originally Posted by Fault View Post
    i started calc 2 yesterday, GAY!
    This has absolutely nothing to do with calc.

  7. #7
    schlumpf's Avatar Retired Noggit Developer

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    Re: lolmath

    = 4-conjuate(x)^2 ( x:= a+bi )
    = 4-(a-bi)^2
    = 4-(a^2-2abi-b^2)
    = 4-a^2+2abi+b^2

  8. #8
    Cypher's Avatar Kynox's Sister's Pimp
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    Re: lolmath

    conjugate(4-x^2)
    = x^2 + 4
    Given:
    a^2 + b^2 = (a-bi)(a+bi)
    Then:
    x^2 + 4 = (x-2i)(x+2i)

  9. #9
    Fearsoldier's Avatar Member
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    Re: lolmath

    And the answer is


    oh sorry my brain exploded

  10. #10
    schlumpf's Avatar Retired Noggit Developer

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    Re: lolmath

    if x := a+bi is element of C then
    x^2 = (a+bi)(a+bi)=(a^2+2abi-b^2)
    conjugate(4-x^2)=conjugate(4-(a^2-b^2+2abi))=4-(a^2-b^2-2abi)=
    =4-(a-bi)(a-bi) BUT NOT =4+x^2!! because x is not a-bi !!
    so simplifing the solution "conjugate(4-x^2)" is not really useful because the solution 4-(conjugate(x)^2) is not much more easy

  11. #11
    Enfeebleness's Avatar Elite User
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    Re: lolmath

    This question is not googleable.

    New question plz.

  12. #12
    Loveshock's Avatar Whip it whip it real hard
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    Re: lolmath

    /Initiate brain explosion


  13. #13
    Mr. Moose's Avatar Member
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    Re: lolmath

    The answer is: impossible?

  14. #14
    Epic Sheep's Avatar Member
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    Re: lolmath

    Originally Posted by Enfeebleness View Post
    This question is not googleable.

    New question plz.
    What he said...:confused:um im second set year 11 this is some hard Shit...i know the anser though....



    PIE!...i mean Pi

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